if you don't want to use javascript then show below code how to display image from db to control.
<form id="form1" runat="server">
<div>
</div>
<asp:ImageButton ID="ImageButton1" ImageUrl="~/Displaypicture.aspx?ImageID=1" runat="server" />
</form>
Codebehind of Displaypicture.aspx:
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Set the backgound image in Lable to retrieve image,
or
read image and show in label as
The sample code follows
public void ProcessRequest (HttpContext context)
{
SqlConnection myConnection = new SqlConnection(“YourConnectionString”);
myConnection.Open();
string sql = "Select Image_Content from ImageGallery where Img_Id=@ImageId";
SqlCommand cmd = new SqlCommand(sql, myConnection);
cmd.Parameters.Add("@ImageId", SqlDbType.Int).Value = context.Request.QueryString["id"];
cmd.Prepare();
SqlDataReader dr = cmd.ExecuteReader();
dr.Read();
string str;
str = "<table>";
str = str + "<tr><td>";
str = str + "<img id='img' runat='server' src=" + dr["Image_Content"].ToString() + "/>"';
str = str + "</td></tr>";
str = "</table>";
lblImage.Text = str.ToString();
dr.Close();
myConnection.Close();
}